Question 16. Answer: The elements of s and p-block are collectively called representative or main group elements. (a) F > Cl> O > N (b) F > O > Cl> N (c) Cl> F > O > N (d) O > F > N > Cl (ii)There are groups numbered from 1 to 18 from the left. In that case energy has to be supplied. Question 1. All the questions has been solved by experts and explained in detail. Answer: They have fully filled s-orbitals and hence have no tendency to accept an additional electron. For example. Chapter wise science formulas consist of all-important points of the chapter. Mendeleev arranged elements in horizontal rows and vertical columns of a table in order of their increasing atomic weights in such a way that the elements with similar properties occupied the same vertical column or group. N7 = 1s2 2s2 2px1 2py1 2pz1 (ii) O has lower ∆iH1 than N and F? Question 26. These questions are created by experts and are as per the latest exam pattern. What are representative elements? Question 29. Question 6. Question 2. What are the various factors due to which the ionization enthalpy of the main group elements tends to decrease down the group? In Ga there is 10 3d electrons which do not screen as is done by S and P electrons. Download Chemistry Notes PDF for class 11 FREE only at BYJU'S. The first half of the elements were placed in the upper left corner and the second half in the lower right corner of each box. CBSE Class 11 Chemistry: Important Topics and Tips for Final Exams. Ans. Ans. The values of ∆ i H1, ∆ iH2 and ∆egH match that of I (Iodine). (d) none of the factors because their size is the same You are the right place to get all information about Mensuration class 8 maths chapter 11. F —> F– What are its units? They are generally paramagnetic in nature. Answer : Boyle’s law is applicable to those gases which have no forces of attraction among the molecules.Such gases are ideal.So Boyle’s law is applicable to only ideal gases.Its formula is PV=K when n and T are constant. Define the term ionization enthalpy? (iii)There were seven periods to accommodate more elements the period 4, 5, 6 and 7 were divided into two halves. (e)9. Students can also download CBSE Class 11 Chemistry Chapter wise question bank pdf and access it anytime, anywhere for free. Both ionisation enthalpy and I electron gain enthalpy are generally expressed with respect to the ground state ofan atom only. This is because after losing an electron, sodium attains the stable noble gas configuration. It is linked with electron gain enthalpy and electronegativity. (a) What is common in them? Which of the following species are not known? Answer: (i) The effective nuclear charge of magnesium is higher than that of sodium. Question 4. (b) 2. (i)There are in all 18 vertical columns i.e. Cation is formed by the loss of one or more electron from the gaseous atom, but the nuclear charge remains the same. 10.The size of an atom can be expressed by three radii. Answer: (i) F2 < Cl2 < 02 < N2 Teachers and Students can access the Class 11 Chapter-wise Chemistry NCERT Solutions by clicking the direct links provided on this page. The normal oxide formed by the element on extreme left is the most basic (eg. Why are they called rare earth metals? Topics and Subtopics in NCERT Solutions for Class 11 Chemistry Chapter 3 Classification of Elements and Periodicity in Properties: NCERT Solutions Class 11 ChemistryChemistry Lab ManualChemistry Sample Papers. Students your final exams are just around the corner. Assign the position of the element having outer electronic configuration, Energy of an electron in the ground state of the hydrogen atom is- 2.18 x 10-18 J.Calculate the ionization enthalpy of atomic hydrogen in terms of JMol-1. Chemistry Class 11 Chapter 4 - Chemical Bonding and Molecular Structure. The values of ∆ i H1, ∆ iH2 and ∆egH match that of Mg (magnesium). (b) valence principal quantum number (n) The formulae list covers all formulae which provides the students a simple way to study of revise the chapter. Name two such triads. This process may be represented as M (g) + ∆iH -> M+ (g) + e–(g) 10. Q.1. 4.Give the main features of p-block elements. The ionization enthalpies keep on decreasing regularly as we move down a group from one element to the other. (1) Synthetic fibres such as terylene ,nylon ,rayon which … because the addition of one or more electrons would result in increased repulsion among the electrons and a decrease in effective nuclear charge. Write Bond Line Formulas For 2,3-dimethyl Butanal . Na+ = 1s2 2s2 2p6 Question 3. The second electron gain enthalpy is positive because energy is needed to overcome the force of repulsion between monovalent anion and second incoming electron. Ans- Understand chapter before revising the science formulas to learn chapter wise science formulas one must have very clear idea about the chapter. Characteristics of d-block elements: Question 10. Which of the above elements is likely to be: What is the cause of periodicity in properties of the elements? Question 35. Which has a larger radius? Answer: (i) n = 3 Answer: Electronic configuration of Na and Mg are The process may be represented by The vertical columns were called groups and the horizontal rows were called periods. Question 2. charge remains the same. They are generally heavy metals having high melting and boiling points. (a) How does atomic radius vary in group in the periodic table? Why do Na and K have similar properties? Which one of the following is isoelectronic with Ne? Ans. Answer: Main features of long form of periodic table: Advantages of long form of periodic table: Question 2. Anything that influences the valence electrons will affect the chemistry of the element. Related Class 11 Notes Chapter-wise: Class 11 Physics Notes; Class 11 Biology Notes; Class 11 Chemistry Notes; The CBSE Class 11 Maths Formulae are cumulated by our panel of highly experienced teachers after analyzing the past 10 years of examination papers and material so that no important formula is left behind. (e) the metal which can form a stable binary halide of the formula MX2(X = halogen) of sodium is higher than that of magnesium. From left to right across a period atomic radii generally decreases due 0->O– (b) Explain And it is known fact that Van der walls radius is always greater than covalent radius. The reason for the deviation is due to the smaller size of F. Due to its small size, the electron repulsions in the relatively compact 2p-subshell are comparatively large and hence the attraction for incoming electron is less as in the case of Cl. CBSE Class 11 Maths formulas available for Chapterwise on Vedantu.com. Chapter 4 Chemical Bonding And Molecular Structure. Ch 2 Chemistry Class 11 - Relation Between Various Models and Bohr's Theory. Chapter 12 Organic Chemistry - Some Basic Principles and Techniques Q 3.2 | Page 361. Sod.oxide Sod.hydroxide Notes of Chemistry for Class 9. (d) 4. What is screening or shielding effect? Explain. Browse further to download free CBSE Class 11 Chemistry Worksheets PDF. Variable oxidation states are generally shown by these elements. Why Li and Mg show resemblance in chemical behaivour? Give their general electronic configuration. First electron in both cases has to be removed from 3s-orbital but the nuclear charge of Na (+ 11) is lower than that of Mg (+ 12) therefore first ionization energy of sodium is lower than that of magnesium. NCERT Exemplar Class 11 Chemistry is very important resource for students preparing for XI Board Examination. Screening or shielding effect of inner shell electron. Students are busy with their last minute revisions and trying to get the most out of their study hours these days. Ans. Answer: The elements of Group I have only one electron in their respective valence shells and thus have a strong tendency to lose this electron. In contrast, the elements of group 17 have seven electrons in their respective valence shells and thus have strong tendency to accept one more electron to make stable configuration. Radius of orbit. The later has fourteen ∆f electrons with very poor shielding effect. As the screening effect increases, the effective nuclear charge decreases. Question 22. d â block elements :- The elements in which the last electron enters the d â orbitals of their last but one energy level constitute d â block elements. Ans. Give reasons: F~ ion has inert gas configuration, While the gain of one electron by (e) The element VI has low first ionization enthalpy (∆ iH1) but higher than that of alkali metals. Ans. Ans. Question 3. Question 37. It makes the study of elements systematic and simple. Structure of Atom Class 11 Notes Chemistry Chapter 2 • Discovery of Electron—Discharge Tube Experiment In 1879, William Crooks studied the conduction of electricity through gases at low pressure. Group VIII occupy three triads of the elements each i.e. The atomic number of the element is 16. 7.Explain why cations are smaller and anions are larger in radii than their parent atom? For noble gases have positive electron gain enthalpy because energy has to be supplied to the element. This causes increase in size. than going from O —>O– f-block elements: (n – 2)f0-14(n -1) d0-1 ns2 where n = 6 – 7, Question 5. (b) The element II which has the least first ionization enthalpy (∆ i H1) and a low negative electron gain enthalpy (∆egH) is the most reactive metal. Consider the following species: Answer: (i) s-Block elements: ns 1-2 where n = 2 – 7. Ans. Question 24. Discuss briefly the various factors on which ionization enthalpy depends. Question 31. d-block elements show variable oxidation states. (b) Arrange them in order of increasing ionic radii? Thus, F is a stronger oxidising agent than Cl. of electron shells increases and thus the atomic size increases. Therefore, electron gain enthalpies of Be and Mg are positive. Thus the increase in electronegativities across a period is accompanied by an increase in non â metallic properties of elements. Answer: Atomic size. In some cases, like in noble gas, atoms do not have any attraction to gain an electron. The compound A is (a ) Ethyl acetate (b) Sodium acetate (c) Sodium propionate (d) Sodium ethoxide. NCERT Solutions of Chapter 3 Class 11 Trigonometry is available free at teachoo. 7. Question 6. ‘. (a)ionization enthalpy increases for each successive electron. For these reasons, the energy required to remove an electron from magnesium is more than the energy required in sodium. The physical and chemical properties of the elements are periodic functions of their atomic numbers. 16.The atomic number of an element is 16. It lies in fourth period and III B group. Question 3. Which of the following statements related to the modem periodic table is incorrect? The elements in the same group have similar properties due to their outer-most (valence shell) configuration. The maximum chemical reactivity at the extreme left (among alkali metals) is exhibited due to the loss of an electron leading to the formation of a cation due to low ionization enthalpy and at the extreme right (among halogens) shown by the gain of an electron forming an anion. Variation within a group. 15. Na2O) whereas that formed by the element on extreme right is the most acidic (eg. Chemistry for Class 11 is divided into 3 parts Organic (2 chapters), Inorganic (5 chapters), and Physical (7 chapters). (i)Mg or Ca (ii) S or Cl CBSE CBSE (Science) Class 11 Textbook ... Chapter 12: Organic Chemistry - Some Basic Principles and Techniques [Page 361] Q 3.2 Q 3.1 Q 3.3. Ans. Question 8. After the loss of first electron, Na+ formed has the electronic configuration of neon (2, 8). The increasing order of reactivity among group 1 elements is Li < Na < K < Rb < Cs whereas that of group 17 is F > Cl > Br > I. Ans. Ans. =1s2 2s2 2p6 3s2 3p6 3d10 4s1 n – 4, period = 4 Block = d Electronic configuration of D (Z = 36) Consequently, the force of attraction by the nucleus for the valence shell electrons decreases and hence the ionization enthalpy decreases. Which important property did Mendeleev use to classify the elements in this periodic table and did he stick to that? B Al Ga In Tl Get the chapter wise weightage for NEET, to know your most important topics for NEET in each of Biology, Chemistry & Physics. (b) Which has the largest atomic radius? Therefore, among F, O and N, oxidising power decreases in the order: F > O > N. However, within a group, oxidising power decreases from top to bottom. Fourth period and decreases down the group group atomic radius ;... Maths formulas for! And inner transition elements bigger size of Al Solutions of Chapter 3 Class 11 Chemistry and! A decrease in non â metallic character of K, Mg, Na, P..... Viii occupy three triads of the p-block elements show variable oxidation states generally. Also the properties of the elements each i.e 12 in the periodic table correct to say that the electronegativity nitrogen! Provided with this article article of JEE Mains and Advanced: Click here 13 CBSE 11 Chemistry Chapter gases... Are in all the orbitals in a group energy state and they neither nor. 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